Results

• Copy of PSF Bylaws Prior to March 2009 Members' Meeting

  ...5.2. Qualification. Directors need not be residents of Delaware or of the United States nor members of the corporation. Section 5.3. Compensation. The Board of Directors shall have authority to fix the compensation of directors unless otherwise provided in the Certificate of Incorporation. Section 5.4. Number. The corporation shall initially have seven (7) directors. Thereafter, the number of directors shall be fixed by the members at each annual meeting of members. Section 5.5. Election an...

• Python 2.4.1 - Release Notes

  ...5942, 726150, 726446, 726869, 727051, 727719, 727719, 727805, 728277, 728563, 728656, 729096, 729103, 729293, 729297, 729300, 729317, 729395, 729622, 729817, 730170, 730296, 730594, 730685, 730826, 730963, 731209, 731403, 731504, 731514, 731626, 731635, 731643, 731644, 731644, 731689, 732124, 732143, 732234, 732284, 732284, 732479, 732761, 732783, 732951, 733667, 733781, 734118, 734231, 734869, 735051, 735293, 735527, 735613, 735694, 736962, 736962, 737970, 738066, 739313, 740055, 740234, 740301...

• Unifying types and classes in Python 2.2

  ...3(C1, C2): __metaclass__ = M3 class D(C2, C3): __metaclass__ = M1 class C4: __metaclass__ = M4 class E(C3, C4): pass For class C2, the constraint is satisfied because M2 is a subclass of M1. For class C3, it is satisfied because M3 is a subclass of both M1 and M2. For class D, the explicit metaclass M1 is not a subclass of the base metaclasses (M2, M3), but choosing M3 satisfies the constraint, so D.__class__ is M3. However, class E ...

• Unifying types and classes in Python 2.2

  ...3(C1, C2): __metaclass__ = M3 class D(C2, C3): __metaclass__ = M1 class C4: __metaclass__ = M4 class E(C3, C4): pass For class C2, the constraint is satisfied because M2 is a subclass of M1. For class C3, it is satisfied because M3 is a subclass of both M1 and M2. For class D, the explicit metaclass M1 is not a subclass of the base metaclasses (M2, M3), but choosing M3 satisfies the constraint, so D.__class__ is M3. However, class E ...

• Unifying types and classes in Python 2.2

  ...3(C1, C2): __metaclass__ = M3 class D(C2, C3): __metaclass__ = M1 class C4: __metaclass__ = M4 class E(C3, C4): pass For class C2, the constraint is satisfied because M2 is a subclass of M1. For class C3, it is satisfied because M3 is a subclass of both M1 and M2. For class D, the explicit metaclass M1 is not a subclass of the base metaclasses (M2, M3), but choosing M3 satisfies the constraint, so D.__class__ is M3. However, class E ...

• Unifying types and classes in Python 2.2

  ...3, it is satisfied because M3 is a subclass of both M1 and M2. For class D, the explicit metaclass M1 is not a subclass of the base metaclasses (M2, M3), but choosing M3 satisfies the constraint, so D.__class__ is M3. However, class E is an error: the two metaclasses involved are M3 and M4, and neither is a subclass of the other. We can fix this latter case as follows: # A new metaclass class M5(M3, M4): pass # Fixed class E class E(C3, C4): __metaclass__ = M5 (The ap...

Python language documentation

If you didn't find what you need, try your search in the Python language documentation.