How to get the path of current running python script?

[Tim Williams (gmail)]

On 20/12/05, Kevin Yuan <farproc at gmail.com> wrote:
>
> I tried the following
>
> >>>> getFilePath = lambda name: os.path.normpath('%s\\%s' % (sys.modules[name].prefix,
> sys.modules[name].__name__))
> >>>> getFilePath('__main__')
>


getFilePath =  sys.argv[0]    ??


:)
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