How to get the path of current running python script?

[Kevin Yuan]

I tried the following

>>>> getFilePath = lambda name: os.path.normpath('%s\\%s' %
(sys.modules[name].prefix,
sys.modules[name].__name__))
>>>> getFilePath('__main__')
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
  File "<interactive input>", line 1, in <lambda>
AttributeError: 'module' object has no attribute 'prefix'
>>>>

Can you help me?
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