re.sub replacement text \-escapes woe
Alexander Schmolck
a.schmolck at gmx.net
Fri Feb 13 18:35:36 EST 2004
Sorry if I missed something obvious, but how do you do this more
intelligently?
def escape(s):
return re.sub(r'([${}\\])', r'\ \1', s).replace('\\ ', '\\')
'as
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