Alexander Schmolck wrote:
> Sorry if I missed something obvious, but how do you do this more
> intelligently?
>
> def escape(s):
> return re.sub(r'([${}\\])', r'\ \1', s).replace('\\ ', '\\')
>
> 'as
Interesting. No direct attack, but another workaround:
re.sub(r'([${}\\])', lambda m: '\\' + m.group(), s)
Peter