Defining a code object from a function

[Emile van Sebille]

In this example, you should be able to do:

retvals = inspect.getargs(plate.hasMoreRows.func_code)

HTH,
--

Emile van Sebille
emile at fenx.com

---------
"Neil Benn" <neil.benn at cambridgeantibody.com> wrote in message
news:3acc9132$0$12241$ed9e5944 at reading.news.pipex.net...
> Hello,
>
>             I have a class as follows:-
>
>
> class plate:
>
>     NoColumns = 0
>     NoRows = 0
>
>     currentRow = 0
>
>     def __init__(self):
>         print "creating plate"
>         print "created plate"
>
>     def hasMoreRows(self):
>         if currentRow < noRows:
>             return 1ist
>         else:
>             return 0
>
>     def nextRow(self):
>         self.currentRow = self.currentRow + 1
>         return self.currentRow
>
>     I'm using the inspect module to get information about the method
> arguments back.
>
> However...................
>
> My problem is that the getargs methods of inspect want a code object.
> Looking through the docs on Python.org I can't work out how to convert a
> method call to a code object so that I can then get the arguments back.
>
>     Please could someone advise me, pretty please?
>
> Cheers,
>
> Neil Benn
> Automation Informatics Scientist
> CaT
>
>