Defining a code object from a function

[Steve Purcell]

Neil Benn wrote:
>     I'm using the inspect module to get information about the method
> arguments back.
> 
> However...................
> 
> My problem is that the getargs methods of inspect want a code object.
> Looking through the docs on Python.org I can't work out how to convert a
> method call to a code object so that I can then get the arguments back.
> 
>     Please could someone advise me, pretty please?


Try this:

    >>> import inspect
    >>> class Foo:
    ...   def method(self, arg1, arg2="something"):
    ...     pass
    ... 
    >>> f = Foo()             
    >>> inspect.getargs(f.method.im_func.func_code)
    (['self', 'arg1', 'arg2'], None, None)


-Steve

-- 
Steve Purcell, Pythangelist
Get testing at http://pyunit.sourceforge.net/
Any opinions expressed herein are my own and not necessarily those of Yahoo