Defining a code object from a function

[Neil Benn]

Hello,

            I have a class as follows:-


class plate:

    NoColumns = 0
    NoRows = 0

    currentRow = 0

    def __init__(self):
        print "creating plate"
        print "created plate"

    def hasMoreRows(self):
        if currentRow < noRows:
            return 1ist
        else:
            return 0

    def nextRow(self):
        self.currentRow = self.currentRow + 1
        return self.currentRow

    I'm using the inspect module to get information about the method
arguments back.

However...................

My problem is that the getargs methods of inspect want a code object.
Looking through the docs on Python.org I can't work out how to convert a
method call to a code object so that I can then get the arguments back.

    Please could someone advise me, pretty please?

Cheers,

Neil Benn
Automation Informatics Scientist
CaT