[Tutor] A sorted dictionary (of sorts)

[Ed Connell]

Thanks for your comments and advice.

Ed

On Thu, Sep 29, 2022 at 12:46 PM Mats Wichmann <mats at wichmann.us> wrote:

> On 9/29/22 08:29, Ed Connell wrote:
> > Hi,
> >
> > The following works fine, but it always made me nervous because
> > ordinary dictionaries  are not supposed  to be sorted.  It works (for
> > now).  Should I worry that some new version of python will break things?
> >
> >      # produce a sorted dictionary
> >      sorted_names = sorted( Team_Calc_d, key = lambda e: Team_Calc_d[ e
> > ].current_power,
> >          reverse = True ) # sorted by current power
> >      TeamPwrSorted_Result_d = {}
> >      for tm in sorted_names:
> >          # setup SortTeams_PowerResult_Dict and copy from Analysis
> objects
> >          # to Results objects
> >          TeamPwrSorted_Result_d[ tm ] = Results( Team_Basics_d[ tm
> > ].start_power )
> >          # create the dictionary
> >          TeamPwrSorted_Result_d[ tm ].current_power = Team_Calc_d[ tm
> > ].current_power
> >
> >      needs_processing = False # we just updated
> >
> >      return TeamPwrSorted_Result_d
> >
>
>
> It's unlikely anything will breaks because you aren't using internals.
>
> If you want to "check your work" against a fairly well known
> implementation (which may have different aims than yours), take a look
> at Grant Jenks' stuff.
>
> https://grantjenks.com/docs/sortedcontainers/sorteddict.html
>
>
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