[Tutor] A sorted dictionary (of sorts)

[Mats Wichmann]

On 9/29/22 08:29, Ed Connell wrote:
> Hi,
> 
> The following works fine, but it always made me nervous because
> ordinary dictionaries  are not supposed  to be sorted.  It works (for
> now).  Should I worry that some new version of python will break things?
> 
>      # produce a sorted dictionary
>      sorted_names = sorted( Team_Calc_d, key = lambda e: Team_Calc_d[ e
> ].current_power,
>          reverse = True ) # sorted by current power
>      TeamPwrSorted_Result_d = {}
>      for tm in sorted_names:
>          # setup SortTeams_PowerResult_Dict and copy from Analysis objects
>          # to Results objects
>          TeamPwrSorted_Result_d[ tm ] = Results( Team_Basics_d[ tm
> ].start_power )
>          # create the dictionary
>          TeamPwrSorted_Result_d[ tm ].current_power = Team_Calc_d[ tm
> ].current_power
> 
>      needs_processing = False # we just updated
> 
>      return TeamPwrSorted_Result_d
> 


It's unlikely anything will breaks because you aren't using internals.

If you want to "check your work" against a fairly well known 
implementation (which may have different aims than yours), take a look 
at Grant Jenks' stuff.

https://grantjenks.com/docs/sortedcontainers/sorteddict.html