[Tutor] Root and power

[Alan Gauld]

On 29/07/15 04:29, Job Hernandez wrote:
> How is it going tutors?
>
> The following problem seems impossible to me:

I made a reply in the thread 'Abs' started on July 27th.

Basically you can use the pow() function.

The power lies between 1-5.
The largest root will be the same as the user input
since X**1 = X. So you always have at least 1 answer!

You need to iterate up to the power of 1 solution to
find if there is a smaller pair of integers.
Some may have several, for example 16 yields:

16**1
4**2
2**4

Your assignment doesn't make it clear how that should be handled...

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Alan G
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