[Tutor] [wxPython-users] How to save file name of file opened from wx.FileDialog ?

[Varsha Purohit]

Hello Everyone,
        In my application i need to select a file using open dialog
box. And then i dont need to open the file. I just need to display the
name of the selected file in a text control. And then open the file in
later part of the program.  But i am not able to get the file name and
display it in the text control. Here is the sample code.

import wx
import os

Fname = '' #Global variable to hold the file name.
class ScrolledWindow(wx.Frame):
    def __init__(self, parent, id, title):
        wx.Frame.__init__(self, parent, id, title, size=(350, 300))
        panel = wx.Panel(self, -1)
        txt1 = wx.TextCtrl(panel, -1, pos=(30, 100), size=(150, 20))
        button11 = wx.Button(panel, -1, "Open", pos=(200,100))
        self.Bind(wx.EVT_BUTTON, self.OnOpen, button11)
        txt1.write(Fname)

        self.Centre()
        self.Show()

    def OnOpen(self,event):
        self.dirname = ''
        dlg = wx.FileDialog(self, "Choose a file", self.dirname,"",
"*.*", wx.OPEN)
        if dlg.ShowModal()==wx.ID_OK:
            self.filename=dlg.GetFilename()
            Fname = self.filename
            self.dirname=dlg.GetDirectory()
        dlg.Destroy()

app = wx.App()
ScrolledWindow(None, -1, 'Aliens')
app.MainLoop()


Any help is appreciated....

thanks,
-- 
Varsha Purohit,
Graduate Student