[Tutor] Checking in lists

[Jason Massey]

John,

Basically it's not evaluating it the way you think it is:

Your first example really equates to:

if (1 or 5) in rollList:
   etc...

(1 or 5) equals 1  and 1 isn't in the your list.



On 4/26/06, John Connors <oztriking at hotmail.com> wrote:
>
> G'day,
>
> I found something today that has me confused. I'm making a list of 6
> random
> dice rolls and I want to check if any 1's or 5's were rolled. I tried this
> way first and it returns true even if there are no 1's or 5's. I'll use a
> roll of all 2's as an example.
>
> rollList = [2,2,2,2,2,2]
> if 1 or 5 in rollList:
>    print 'yes'
> else:
>    print 'no'
>
> Then I tried this and it works fine.
>
> rollList = [2,2,2,2,2,2]
> if 1 in rollList or 5 in rollList:
>    print 'yes'
> else:
>    print 'no'
>
> It doesn't really matter because the second way does what I want but I
> would
> like to know why the first way doesn't work and if the syntax is wrong why
> doesn't it return an error.
>
> John
>
> PS I apologise if this is a duplicate, hotmail did some kind of spam check
> when I tried to send it, I've waited 30 mins and I don't think it went the
> 1st time so I'll post it again.
>
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