[Python-checkins] Prepare private _rank() function to be made public. (#96372)
rhettinger
webhook-mailer at python.org
Mon Aug 29 00:42:06 EDT 2022
https://github.com/python/cpython/commit/d8d55d13fc502ed79081e2c73d5d8cb034a8b577
commit: d8d55d13fc502ed79081e2c73d5d8cb034a8b577
branch: main
author: Raymond Hettinger <rhettinger at users.noreply.github.com>
committer: rhettinger <rhettinger at users.noreply.github.com>
date: 2022-08-28T23:41:58-05:00
summary:
Prepare private _rank() function to be made public. (#96372)
files:
M Lib/statistics.py
diff --git a/Lib/statistics.py b/Lib/statistics.py
index a3f915c1302..b4676fed5e2 100644
--- a/Lib/statistics.py
+++ b/Lib/statistics.py
@@ -355,7 +355,8 @@ def _fail_neg(values, errmsg='negative value'):
raise StatisticsError(errmsg)
yield x
-def _rank(data, /, *, key=None, reverse=False, ties='average') -> list[float]:
+
+def _rank(data, /, *, key=None, reverse=False, ties='average', start=1) -> list[float]:
"""Rank order a dataset. The lowest value has rank 1.
Ties are averaged so that equal values receive the same rank:
@@ -369,14 +370,22 @@ def _rank(data, /, *, key=None, reverse=False, ties='average') -> list[float]:
>>> _rank([3.5, 5.0, 3.5, 2.0, 6.0, 1.0])
[3.5, 5.0, 3.5, 2.0, 6.0, 1.0]
- It is possible to rank the data in reverse order so that
- the highest value has rank 1. Also, a key-function can
- extract the field to be ranked:
+ It is possible to rank the data in reverse order so that the
+ highest value has rank 1. Also, a key-function can extract
+ the field to be ranked:
>>> goals = [('eagles', 45), ('bears', 48), ('lions', 44)]
>>> _rank(goals, key=itemgetter(1), reverse=True)
[2.0, 1.0, 3.0]
+ Ranks are conventionally numbered starting from one; however,
+ setting *start* to zero allow the ranks to be used as array indices:
+
+ >>> prize = ['Gold', 'Silver', 'Bronze', 'Certificate']
+ >>> scores = [8.1, 7.3, 9.4, 8.3]
+ >>> [prize[int(i)] for i in _rank(scores, start=0, reverse=True)]
+ ['Bronze', 'Certificate', 'Gold', 'Silver']
+
"""
# If this function becomes public at some point, more thought
# needs to be given to the signature. A list of ints is
@@ -389,7 +398,7 @@ def _rank(data, /, *, key=None, reverse=False, ties='average') -> list[float]:
if key is not None:
data = map(key, data)
val_pos = sorted(zip(data, count()), reverse=reverse)
- i = 0 # To rank starting at 0 instead of 1, set i = -1.
+ i = start - 1
result = [0] * len(val_pos)
for _, g in groupby(val_pos, key=itemgetter(0)):
group = list(g)
@@ -400,6 +409,7 @@ def _rank(data, /, *, key=None, reverse=False, ties='average') -> list[float]:
i += size
return result
+
def _integer_sqrt_of_frac_rto(n: int, m: int) -> int:
"""Square root of n/m, rounded to the nearest integer using round-to-odd."""
# Reference: https://www.lri.fr/~melquion/doc/05-imacs17_1-expose.pdf
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