[Chicago] Resolving lists within lists within lists within .....

[Lewit, Douglas]

Thanks Daniel,

I'll go check it out.

Hope you had a nice Valentine's Day.

Best,

Douglas.


On Mon, Feb 15, 2016 at 4:31 PM, Daniel Galtieri <daniel.galtieri at gmail.com>
wrote:

> Look at itertools.chain(), basically does what you want.
> On Feb 15, 2016 4:12 PM, "Lewit, Douglas" <d-lewit at neiu.edu> wrote:
>
>> Hi everyone,
>>
>> Well it's President's Day and I've got the day off!  Hooray!!!  Finally
>> some time to just relax and mess around.  So I'm at my computer playing
>> around with Python and wondering how to resolve the issue of multiple lists
>> embedded within other lists.  I came up with two functions that I think
>> solve the problem.  But I was wondering if Guido or someone else added a
>> builtin function or method that does this automatically for the
>> programmer.  Or is there an easier way?  Okay.... thanks.  ( In case you're
>> wondering why I called the function "flatten" it's because I know from
>> experience that Wolfram Mathematica and Ocaml have these "flatten"
>> functions.  I think Ruby has something similar, but I haven't played with
>> Ruby in a while so I'm not really sure. )  The try: except block is
>> important because you can't subscript non-list data structures in Python.
>> The IndexError is what you get when you try to index an empty list.  So I
>> ****think**** my try: except block covers most commonly encountered
>> exceptions when working with lists embedded within other lists.
>>
>> Best,
>>
>> Douglas.
>>
>> def flatten(lst):
>> if lst == [ ]:
>> return lst
>> else:
>> try:
>> return [lst[0][0]] + flatten(lst[0][1:] + lst[1:])
>> except TypeError:
>> return [lst[0]] + flatten(lst[1:])
>> except IndexError:
>> return flatten(lst[1:])
>>
>> def flattenAgain(lst):
>> newList = lst[:]
>> while newList != flatten(newList):
>> newList = flatten(newList)
>> return newList
>>
>>
>>
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