[Pythonmac-SIG] correct way to create a PyObjC application

[davelist at mac.com]

I've done a little bit Cocoa programming using Objective-C and tried  
PyObjc back under Xcode/IB 2.0, but now I'd like to try PyObjc with  
Xcode/IB 3. Using a mixture of documentation, here's what I've come up  
with. Can someone please let me know if there's anything wrong with  
this process or if there is a much easier way (I'm not complaining -  
this seems pretty simple to me) to create a simple PyObjc app (no  
bindings, or existing controller classes, etc.) using the Leopard  
System python/pyobjc (i.e., the python that comes with Leopard).

1. In Xcode 3, create a Cocoa Python Objc Application
2. add a new Python file that will be the controller
3. click on MainMenu.xib to open IB
4. create interface
5. drag a NSObject to IB MainMenu.xib window (I believe this is  
referred to as the Doc window)
5. in the IB Inspector window do the following
5.1 change the Class Identity to the Python controller class I just  
created
5.2 add outlets for the widgets I need to access in the Class Outlets  
section
5.3 add actions (no underscores in names, end in a colon) in the Class  
Actions section
6. Control mouse drag from Controller in Doc Window to each widget and  
set the outlet
7. Control mouse drag from Buttons, etc. to the Controller and set the  
action
8. in Controller Python file:
8.1 add a line for each outlet right under class definition that looks  
like: outletName = objc.IBOutlet() (this will allow methods to access  
the outlet as self.outletName
8.2 create methods that match action names changing colon to  
underscore (i.e., def buttonPressed_(self, sender); one web page said  
add @objc.IBAction above those methods but that didn't seem necessary)
9. in generated main.py, add import statement for my Python controller  
file
10. Build and Go

This seems to work for me and if I tell it to build a universal app  
and use the Release build, I can even copy the release build .app to  
other machines and run it.

Thanks,
Dave