A missing iterator on itertools module?

[ast]

Le 28/03/2024 à 18:07, Stefan Ram a écrit :
> ast <none at none.fr> wrote or quoted:
>> s1 = "AZERTY"
>> s2 = "QSDFGH"
>> s3 = "WXCVBN"
>> and I need an itertor who delivers
>> A Q W Z S C E D C ...
>> I didn't found anything in itertools to do the job.
>> So I came up with this solution:
>> list(chain.from_iterable(zip("AZERTY", "QSDFGH", "WXCVBN")))
> 
>    Maybe you meant "zip(s1,s2,s3)" as the definition of s1, s2,
>    and s3 otherwise would not be required. Also the "list" is not
>    necessary because "chain.from_iterable" already is an iterable.
>    You could also use "*" instead of "list" to print it. So,
> 
> import itertools as _itertools
> s =[ "AZERTY", "QSDFGH", "WXCVBN" ]
> print( *_itertools.chain.from_iterable( zip( *s )))
> 
>    . But these are only minor nitpicks; you have found a nice solution!

Why did you renamed itertools as _itertools ?