re.search - Pattern matching review
Ganesh Pal
ganesh1pal at gmail.com
Sat May 28 14:12:15 EDT 2016
Dear Python friends,
I am on Python 2.7 and Linux . I am trying to extract the address
"1,5,147456:8192" from the below stdout using re.search
(Pdb) stdout
'linux-host-machine-1: Block Address for 1,5,27320320:8192 (block
1,5,147456:8192) --\nlinux-host-machine-1: magic
0xdeaff2fe mark_cookie 0x300000000000000a\n'
(Pdb) type(stdout)
<type 'str'>
Here is the code I have come up with, this looks buggy please review
the same and suggest any better ways to code the same
the same may be splitlines() , re.complie() etc , my intention is to
just match 1,5,147456:8192 and return the same.
#Sample code
import re
import subprocess_run
def get_block():
try:
cmd = "get_block_info -l"
# stdout is the output retrieved by subprocess.Popen()
stdout, stderr, exitcode = subprocess_run(cmd)
search_pat = 'Block Address.* \(block (\d+),(\d+),(\d+):(\d+)'
matched = re.search(search_pat, stdout)
block = (int(matched.group(1)),
int(matched.group(2)),
int(matched.group(3)),
int(matched.group(4)),
)
except IOError, e:
logging.warning('Error reading lines from "%s" (%s).'
% (cmd, e))
if block is None:
logging.error("block not found")
return False
logging.info("block not found")
return block
Regards,
Ganesh
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