Break and Continue: While Loops

[Elizabeth Weiss]

On Thursday, June 23, 2016 at 1:06:09 AM UTC-4, Rustom Mody wrote:
> On Thursday, June 23, 2016 at 9:47:23 AM UTC+5:30, Elizabeth Weiss wrote:
> > CODE #1:
> > 
> > i=0
> > while 1==1:
> >    print(i)
> >    i=i+1
> >    if i>=5:
> >      print("Breaking")
> >      break
> > 
> > ------
> > I understand that i=0 and i will only be printed if 1=1
> > The results of this is
> > 0
> > 1
> > 2
> > 3
> > 4
> > Breaking
> > 
> > Why is Breaking going to be printed if i only goes up to 4? It does say if i>=5? Shouldn't this mean that the results should be:
> > 0
> > 1
> > 2
> > 3
> > 4
> > 5
> > 
> > CODE #2:
> > 
> > i=0
> > while True:
> >    i=i+1
> >   if i==2:
> >      print("Skipping 2")
> >      continue
> >   if i==5:
> >      print("Breaking")
> >      break
> >    print(i)
> > 
> > ------
> > 
> > Questions:
> > 1. what does the word True have to do with anything here? 
> > 2. i=i+1- I never understand this. Why isn't it i=i+2?
> > 3. Do the results not include 2 of 5 because we wrote if i==2 and if i==5?
> > 4. How is i equal to 2 or 5 if i=0?
> > 
> > Thanks for all of your help!
> 
> I suggested in your other post (Subject While Loops)
> that the predecessor of python ABC's syntax for assignment would help unconfuse you
> 
> ie the ASSIGNMENT x=y we write as PUT y IN x
> 
> Using that rewrite your CODE 1 as
> 
> PUT 0 in i
> while 1==1:
>    print(i)
>    PUT i+1 IN i
>    if i>=5:
>      print("Breaking")
>      break 
> 
> Now try and rethink what that does
> Then repeat for your other examples that confuse

Got it! Thank you!