Break and Continue: While Loops

[Rustom Mody]

On Thursday, June 23, 2016 at 9:47:23 AM UTC+5:30, Elizabeth Weiss wrote:
> CODE #1:
> 
> i=0
> while 1==1:
>    print(i)
>    i=i+1
>    if i>=5:
>      print("Breaking")
>      break
> 
> ------
> I understand that i=0 and i will only be printed if 1=1
> The results of this is
> 0
> 1
> 2
> 3
> 4
> Breaking
> 
> Why is Breaking going to be printed if i only goes up to 4? It does say if i>=5? Shouldn't this mean that the results should be:
> 0
> 1
> 2
> 3
> 4
> 5
> 
> CODE #2:
> 
> i=0
> while True:
>    i=i+1
>   if i==2:
>      print("Skipping 2")
>      continue
>   if i==5:
>      print("Breaking")
>      break
>    print(i)
> 
> ------
> 
> Questions:
> 1. what does the word True have to do with anything here? 
> 2. i=i+1- I never understand this. Why isn't it i=i+2?
> 3. Do the results not include 2 of 5 because we wrote if i==2 and if i==5?
> 4. How is i equal to 2 or 5 if i=0?
> 
> Thanks for all of your help!

I suggested in your other post (Subject While Loops)
that the predecessor of python ABC's syntax for assignment would help unconfuse you

ie the ASSIGNMENT x=y we write as PUT y IN x

Using that rewrite your CODE 1 as

PUT 0 in i
while 1==1:
   print(i)
   PUT i+1 IN i
   if i>=5:
     print("Breaking")
     break 

Now try and rethink what that does
Then repeat for your other examples that confuse