Is '*args' useful in this example code?

[Antoon Pardon]

Op 05-01-16 om 03:16 schreef Robert:
> Hi,
>
> I find an example code on wrap at this link:
> http://stackoverflow.com/questions/308999/what-does-functools-wraps-do
>
> Here is the code:
> ////////
> def logged(func):
>     def with_logging(*args, **kwargs):
>         print func.__name__ + " was called"
>         return func(*args, **kwargs)
>     return with_logging
> ///////
>
> I understand now, but I feel the args usage is weird. I don't see any way 
> to use *args and **kwargs in above code. What is your opinion on it?
>
>
> Thanks,

You want the following to work

def add(a, b):
    return a + b

def double(n)
    return n + n

logged_add = logged(add)
logged_double = logged(double)

s = logged_add(3, 5)
d = logged_double(13)

-- 
Antoon Pardon