Is '*args' useful in this example code?

[Arif Khokar]

On 01/04/2016 09:16 PM, Robert wrote:
> Hi,
>
> I find an example code on wrap at this link:
> http://stackoverflow.com/questions/308999/what-does-functools-wraps-do
>
> Here is the code:
> ////////
> def logged(func):
>      def with_logging(*args, **kwargs):
>          print func.__name__ + " was called"
>          return func(*args, **kwargs)
>      return with_logging
> ///////
>
> I understand now, but I feel the args usage is weird. I don't see any way
> to use *args and **kwargs in above code. What is your opinion on it?

The reason the inner method has *args, and **kwargs as parameters is so 
that it doesn't have to exactly match the signature of func.  If func 
was a method that took 3 parameters, then if you didn't use *args, you 
would have to define the with_logging method to also take 3 parameters. 
  If func takes one or more keyword parameters, then you would have to 
add that to the definition of the with_logging method if you don't use 
**kwargs.

IOW, using *args and **kwargs in the wrapper method definition removes 
the requirement that its parameter list exactly match func's parameter list.