Check if a given value is out of certain range

[Mark Lawrence]

On 05/10/2015 09:18, Michiel Overtoom wrote:
>
> Why not use a function?
>
>
>      if outside(x, 0, 10):
>          print("x has wrong value")
>      else:
>          print("x has good value")
>
>
> where 'outside' is defined as:
>
>      def outside(value, lowerbound, upperbound):
>          return value < lowerbound or value > upperbound
>
> Greetings,
>

Please wash your mouth out with soap, burn precious clock cycles just to 
make code readable, never I say :)

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence