Check if a given value is out of certain range

[Michiel Overtoom]

Why not use a function?


    if outside(x, 0, 10):
        print("x has wrong value")
    else:
        print("x has good value")


where 'outside' is defined as:

    def outside(value, lowerbound, upperbound):
        return value < lowerbound or value > upperbound  

Greetings,