Multiple thread program problem

[M2]

On Wednesday, June 3, 2015 at 3:41:15 PM UTC-5, M2 wrote:
> Hello
> I am trying to create multiple thread through the below program but I am getting an error 
> 
> #! /usr/bin/python
> import os
> import subprocess
> import thread
> import threading
> from thread import start_new_thread
> 
> def proc(f) :
>         com1="ssh -B "
>         com2=line.strip('\n')
>         com3= " uname -a"
>         co=str("ssh -B ")+ str(com2) + str(" uname -a")
>         subprocess.call(co,shell=True)
>         print "----------------------------"
>         return
> 
> f = open('/tmp/python/1')
> for line in f:
>         t=thread.start_new_thread(proc(f),())
>         t.start()
> f.close()
> c = raw_input(" Type anything to quit")
> 
> 
> Execution output:
> Linux abc.myhomenetwork.com 2.6.18-348.25.1.el5 #1 SMP Thu Apr 10 06:32:45 EDT 2014 x86_64 x86_64 x86_64 GNU/Linux
> ----------------------------
> Traceback (most recent call last):
>   File "./readfile1.py", line 19, in <module>
>     t=thread.start_new_thread(proc(f),())
> TypeError: first arg must be callable

Awesome Cameron.
It works the way I want it to work.

Thanks a lot guys.
Here is the new code:
#! /usr/bin/python
import os
import subprocess
import thread
import threading
from thread import start_new_thread

def proc(col) :
        P=subprocess.Popen(col, shell=True)
        return

f = open('/tmp/python/1')
for line in f:
        com1="ssh -B "
        com2=line.strip('\n')
        #com3= " /var/scripts/health/health.sh"
        com3= " uname -a "
        co=str("ssh -B ")+ str(com2) + str(com3)
        P=proc(co)
f.close()


Thanks a ton guys this should get me started on the greater program I am trying to write.