pad binary string with a given byte value (python 3)

[Peter Otten]

Nagy László Zsolt wrote:

> 
>>> bytes/str.ljust()
>>>
>>>>>> def pad(b, n=16, c=b"\x0f"):
>>> ...     length = (len(b)+n-1)//n*n
>>> ...     return b.ljust(length, c)
>> Thanks!
> One more question. How do I create a single char binary string from a
> number? E.g.
> 
>  >>> bytes([65])
> b'A'
> 
> It seems to be wrong again. The bytes constructor requires a sequence,
> and I don't like creating a list or a tuple just to convert it into a
> binary string.

Unfortunately I'm not aware of a function similar to chr() that creates 
bytes.