pad binary string with a given byte value (python 3)

[Nagy László Zsolt]

>> bytes/str.ljust()
>>
>>>>> def pad(b, n=16, c=b"\x0f"):
>> ...     length = (len(b)+n-1)//n*n
>> ...     return b.ljust(length, c)
> Thanks!
One more question. How do I create a single char binary string from a 
number? E.g.

 >>> bytes([65])
b'A'

It seems to be wrong again. The bytes constructor requires a sequence, 
and I don't like creating a list or a tuple just to convert it into a 
binary string.

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