Example of python service running under systemd?
Ervin Hegedüs
airween at gmail.com
Thu Sep 11 17:29:21 EDT 2014
Hi Travis,
On Thu, Sep 11, 2014 at 02:06:48PM -0700, Travis Griggs wrote:
>
> On Sep 11, 2014, at 11:18 AM, Chris “Kwpolska” Warrick <kwpolska at gmail.com> wrote:
>
> > Depends what you want.
>
> Mine is not a web service. My main.py looks like this:
>
> #!/usr/bin/env python3
>
> import cycle
> import pushTelemetry
> from threading import Thread
>
> def main():
> Thread(target=pushTelemetry.udpLoop).start()
> Thread(target=cycle.cycleLoop).start()
>
> if __name__ == '__main__':
> main()
>
> It basically creates two threads, one which does some local processing and control, the other which periodically does reporting via udp packets. I use the dual threads because they both work with a shared serial port at times, so I have to synchronize access through that.
>
> What I want is to have this startup, after my board has it’s networking layer up and running (and hopefully a valid ip address by then), and to just keep running forever
may be you think about the fork(), eg:
if __name__ == "__main__":
...other codes, eg. drop root privileges, ...
...check arguments...
try:
pid = os.fork()
if pid > 0:
#print "Daemon started (pid: %d)" % (pid)
sys.exit(0)
except OSError, e:
print >>sys.stderr, "fork #1 failed: %d (%s)" % (e.errno, e.strerror)
sys.exit(1)
os.chdir("/")
os.setsid()
os.umask(0)
# do second fork
try:
pid = os.fork()
if pid > 0:
#print "Daemon started (pid: %d)" % (pid)
sys.exit(0)
except OSError, e:
print >>sys.stderr, "fork #2 failed: %d (%s)" % (e.errno, e.strerror)
sys.exit(1)
main()
regards,
a.
--
I � UTF-8
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