spilt question

[Dave Angel]

On 05/16/2013 11:15 AM, Chris Angelico wrote:
> On Fri, May 17, 2013 at 1:00 AM, loial <jldunn2000 at gmail.com> wrote:
>> I want to split a string so that I always return everything BEFORE the LAST underscore
>>
>> HELLO_xxxxxxxx.lst         # should return HELLO
>> HELLO_GOODBYE_xxxxxxxx.ls  # should return HELLO_GOODBYE
>>
>> I have tried with rsplit but cannot get it to work.
>>
>> Any help appreciated
>
> Try with a limit:
>
>>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)
> ['HELLO_GOODBYE', 'xxxxxxxx.ls']
>>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)[0]
> 'HELLO_GOODBYE'
>
> You can easily get docs on it:
>
>>>> help("".rsplit)
> Help on built-in function rsplit:
>
> rsplit(...)
>      S.rsplit(sep=None, maxsplit=-1) -> list of strings
>
>      Return a list of the words in S, using sep as the
>      delimiter string, starting at the end of the string and
>      working to the front.  If maxsplit is given, at most maxsplit
>      splits are done. If sep is not specified, any whitespace string
>      is a separator.
>
> ChrisA
>

Now that you've all done his homework for him, see if The OP can spot 
the one case where that won't work.  It's easy to test for, but still 
important to get right (for some definition of right).

-- 
DaveA