using "*" to make a list of lists with repeated (and independent) elements

[88888 Dihedral]

88888 Dihedral於 2012年9月27日星期四UTC+8上午6時07分35秒寫道：
> Paul Rubin於 2012年9月27日星期四UTC+8上午5時43分58秒寫道：
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> > TP <TP at frenoespam.fr.invalid> writes:
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> > > copies a list, he copies in fact the *pointer* to the list ....
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> > > Is it the correct explanation?
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> > Yes, that is correct.
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> > > In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*" 
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> > > without this behavior?
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> >     >>> a = [[0]*3 for i in xrange(2)]
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> >     >>> a[0][0]=2
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> >     >>> a
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> >     [[2, 0, 0], [0, 0, 0]]
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> I used numpy before. 
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> Python is not lisp but python can emulate the lisp behaviors.

def zeros(m,n):
	a=[]
	for i in xrange(m):
		a.append([0]*n)
	return a

If  one wants to tranlate to C, this is the style.