using "*" to make a list of lists with repeated (and independent) elements

[88888 Dihedral]

Paul Rubin於 2012年9月27日星期四UTC+8上午5時43分58秒寫道：
> TP <TP at frenoespam.fr.invalid> writes:
> 
> > copies a list, he copies in fact the *pointer* to the list ....
> 
> > Is it the correct explanation?
> 
> 
> 
> Yes, that is correct.
> 
> 
> 
> > In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*" 
> 
> > without this behavior?
> 
> 
> 
>     >>> a = [[0]*3 for i in xrange(2)]
> 
>     >>> a[0][0]=2
> 
>     >>> a
> 
>     [[2, 0, 0], [0, 0, 0]]

I used numpy before. 

Python is not lisp but python can emulate the lisp behaviors.