Comparing strings from the back?

[Johannes Bauer]

On 06.09.2012 15:43, Johannes Bauer wrote:

> Wrong, at least for randomized strings (i.e. every character with the
> same probability). O(N) is worst-case, O(log N) is correct for
> randomized strings.
^^
Here I write the right thing. Then further below...

> Yes, worst-case is O(N), best case O(1). Average is O(n log n).

...I write the wrong thing. O(log n) is what I meant, as Dave correctly
noticed.

Best regards,
Johannes

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