removing nested iffs
Peter Otten
__peter__ at web.de
Sat Jul 30 03:15:51 EDT 2011
Chris Angelico wrote:
> On Sat, Jul 30, 2011 at 6:42 AM, Peter Otten <__peter__ at web.de> wrote:
>> def format_pairs(pairs):
>> for template, value in pairs:
>> if value is None:
>> break
>> yield template.format(value)
>>
>
> Cool! May I suggest a trifling change:
>
> def format_pairs(*pairs):
> for template, value in pairs:
> if value is None: break
> yield template.format(value)
>
> That way, the call can dispense with the [] in the argument list. This
> is a pretty clean solution though, I like it.
Alternatively you can move the list literal into an extra line:
pairs = [
...
]
return "".join(format_pairs(pairs))
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