removing nested iffs
Chris Angelico
rosuav at gmail.com
Fri Jul 29 17:48:57 EDT 2011
On Sat, Jul 30, 2011 at 6:42 AM, Peter Otten <__peter__ at web.de> wrote:
> def format_pairs(pairs):
> for template, value in pairs:
> if value is None:
> break
> yield template.format(value)
>
Cool! May I suggest a trifling change:
def format_pairs(*pairs):
for template, value in pairs:
if value is None: break
yield template.format(value)
That way, the call can dispense with the [] in the argument list. This
is a pretty clean solution though, I like it.
ChrisA
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