HTTP Post Request

kaklis at gmail.com kaklis at gmail.com
Tue May 11 06:29:22 EDT 2010


On May 11, 10:56 am, "kak... at gmail.com" <kak... at gmail.com> wrote:
> On May 11, 5:06 am, Kushal Kumaran <kushal.kumaran+pyt... at gmail.com>
> wrote:
>
>
>
> > On Mon, May 10, 2010 at 8:26 PM, kak... at gmail.com <kak... at gmail.com> wrote:
> > > On May 10, 10:22 am, Kushal Kumaran <kushal.kumaran+pyt... at gmail.com>
> > > wrote:
> > >> On Mon, May 10, 2010 at 7:30 PM, kak... at gmail.com <kak... at gmail.com> wrote:
> > >> > Hi to all, i want to ask you a question, concerning the best way to do
> > >> > the following as a POST request:
> > >> > There is server-servlet that accepts xml commands
> > >> > It had the following HTTP request headers:
>
> > >> >            Host: somehost.com
> > >> >            User-Agent: Jakarta Commons-HttpClient
> > >> >            Content-Type: text/xml
> > >> >            Content-Length: 415
>
> > >> > and the following request body (reformatted here for clarity):
>
> > >> >            <?xml version='1.0'?>
> > >> >            <methodCall>
> > >> >              <methodName>search</methodName>
> > >> >            </methodCall>
> > >> > How can i send the above to the Listener Servlet?
> > >> > Thanks in advance
>
> > >> Use the xmlrpclib module.
>
> > > OK, sending headers with xmlrpclib,
> > > but how do i send the XML message?
>
> > Your XML message is an XML RPC message.  You will use xmlrpclib like this:
>
> > server_proxy = xmlrpclib.ServerProxy(('somehost.com', 80))
> > result = server_proxy.search()
>
> > The call to server_proxy.search will result in an actual XML RPC
> > message being sent.
>
> > Read up on the xmlrpclib documentation here:http://docs.python.org/library/xmlrpclib.html, and the XMLRPC spec
> > here:http://www.xmlrpc.com/spec
>
> > --
> > regards,
> > kushal
>
> Ok I got it!
> Thank you!!!
>
> A.K

Apparently the server i'm trying to connect accepts only POST
connections. So xmlrpclib is useless.
I think I need the httplib library module.

Any hints?

A.K.



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