HTTP Post Request

[kaklis at gmail.com]

On May 11, 5:06 am, Kushal Kumaran <kushal.kumaran+pyt... at gmail.com>
wrote:
> On Mon, May 10, 2010 at 8:26 PM, kak... at gmail.com <kak... at gmail.com> wrote:
> > On May 10, 10:22 am, Kushal Kumaran <kushal.kumaran+pyt... at gmail.com>
> > wrote:
> >> On Mon, May 10, 2010 at 7:30 PM, kak... at gmail.com <kak... at gmail.com> wrote:
> >> > Hi to all, i want to ask you a question, concerning the best way to do
> >> > the following as a POST request:
> >> > There is server-servlet that accepts xml commands
> >> > It had the following HTTP request headers:
>
> >> >            Host: somehost.com
> >> >            User-Agent: Jakarta Commons-HttpClient
> >> >            Content-Type: text/xml
> >> >            Content-Length: 415
>
> >> > and the following request body (reformatted here for clarity):
>
> >> >            <?xml version='1.0'?>
> >> >            <methodCall>
> >> >              <methodName>search</methodName>
> >> >            </methodCall>
> >> > How can i send the above to the Listener Servlet?
> >> > Thanks in advance
>
> >> Use the xmlrpclib module.
>
> > OK, sending headers with xmlrpclib,
> > but how do i send the XML message?
>
> Your XML message is an XML RPC message.  You will use xmlrpclib like this:
>
> server_proxy = xmlrpclib.ServerProxy(('somehost.com', 80))
> result = server_proxy.search()
>
> The call to server_proxy.search will result in an actual XML RPC
> message being sent.
>
> Read up on the xmlrpclib documentation here:http://docs.python.org/library/xmlrpclib.html, and the XMLRPC spec
> here:http://www.xmlrpc.com/spec
>
> --
> regards,
> kushal

Ok I got it!
Thank you!!!

A.K