How to covert ASCII to integer in Python?

[Mensanator]

On May 30, 7:59 pm, Mensanator <mensana... at aol.com> wrote:
> On May 30, 6:44 pm, Joshua Kugler <jkug... at bigfoot.com> wrote:
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> > Skonieczny, Chris wrote:
> > > YOU SHOULD REMOVE or CORRECT YOUR POST here:
> > >http://mail.python.org/pipermail/python-list/2007-February/427841.html
>
> > > It is not true - eg. try :
> > > a='P'            # P is ASCII , isn't it ?
> > > b=int(a)
> > > and what you will get ? An error !!!
>
> > > Or probably you yourself should - quote :
> > > "You probably should go through the tutorial ASAP that is located here:
>
> > >http://docs.python.org/tut/"
>
> > int() converts a strings that is a valid intenter.  What you're looking for
> > is ord().
>
> Possibly. Perhaps the OP wants the position of 'P'
> in the alphabet, in which case he wants b=64-ord(a)
> or b=16.

Oops! I meant ord(a)-64, of course.

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> > In [1]: ord('d')
> > Out[1]: 100
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> > In [2]: a='P'
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> > In [3]: b=ord(a)
>
> > In [4]: b
> > Out[4]: 80
>
> > j