How to covert ASCII to integer in Python?

[Mensanator]

On May 30, 6:44 pm, Joshua Kugler <jkug... at bigfoot.com> wrote:
> Skonieczny, Chris wrote:
> > YOU SHOULD REMOVE or CORRECT YOUR POST here:
> >http://mail.python.org/pipermail/python-list/2007-February/427841.html
>
> > It is not true - eg. try :
> > a='P'            # P is ASCII , isn't it ?
> > b=int(a)
> > and what you will get ? An error !!!
>
> > Or probably you yourself should - quote :
> > "You probably should go through the tutorial ASAP that is located here:
>
> >http://docs.python.org/tut/"
>
> int() converts a strings that is a valid intenter.  What you're looking for
> is ord().

Possibly. Perhaps the OP wants the position of 'P'
in the alphabet, in which case he wants b=64-ord(a)
or b=16.

>
> In [1]: ord('d')
> Out[1]: 100
>
> In [2]: a='P'
>
> In [3]: b=ord(a)
>
> In [4]: b
> Out[4]: 80
>
> j