problems with opening files due to file's path

[Alexnb]

I am using GUI, Tkinter to be exact. But regardless of how the path gets
there, it needs to opened correctly. The problem I am running into is that
the program receives a path of a file, either .wma or .mp3 and is supposed
to open it. I run into problems when there is either a ")" or a number next
to the backslash "\" in the file path. I am looking for a way to make it
work with a variable, I can make it work when I physically type it in, but
not with a variable that holds the path. 



Mike Driscoll wrote:
> 
> On Jun 10, 1:57 pm, Alexnb <alexnbr... at gmail.com> wrote:
>> That would work, but not for what I want. See the file could be anywhere
>> on
>> the user's system and so the entire path will be unique, and that didn't
>> work with a unique path. What is the subprocess module you are talking
>> about?
>>
> 
> 
> <snip>
> 
> As Carsten pointed out, we don't really know what you're doing. Or at
> least, I don't. Why do you even want to do string substitution? How
> does the user navigate to the files that the user wants to open? Are
> you using a GUI or a command line interface?
> 
> Anyway, Google is your friend. Searching for "python subprocess" gives
> you this:
> 
> http://docs.python.org/lib/module-subprocess.html
> 
> Mike
> --
> http://mail.python.org/mailman/listinfo/python-list
> 
> 

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