Python Behind a Squid Corporate Proxy on Windows

Larry Hale larzluv at hotmail.com
Thu Jul 17 12:22:44 EDT 2008


Greetings, Pythonistas!

My employer has a Squid Proxy between my Python programs and The
Internet.

I've searched high-and-low, and can only find examples online of how
to do basic authentication to connect TO an external Web Server, but
not how to go THROUGH a (corporate) Proxy, thus my question here.
I've tried all sorts of permutations based on my findings, but
(obviously) nothing's working for me.  I've come across conflicting
information, including that urllib2 can't/won't do what I'm needing,
though this statement was a couple years old.

I'm running Python 2.5 on Windows XP SP2 64-bit.  The Proxy is Squid
(don't know what version, but can find out if this is relevant).

urllib2 grabs the Proxy info fine: 'http': 'http://webfilter.xyz.local:
3128' (.getproxies()).  There's the obvious necessity of telling
"something" my ID/pass *somehow*.

An example of one iteration:

######################

import urllib2

proxy_handler = urllib2.ProxyHandler( { "http": "http://
myusername:@webfilter.xyz.local:3128" } )
opener        = urllib2.build_opener( proxy_handler )

urllib2.install_opener( opener )

response = opener.open( "http://python.org" )

print response

######################

I've tried situations using HTTPPasswordMgrWithDefaultRealm and its
add_password method, also to no avail.  (Again, THIS sort of thing
seems related to the -external- Web Server, _not_ going *through* a
Proxy.  'Course, I could be wrong.  But if I am, I couldn't get this
to work, either.  ;)

I've looked at what's happening with Wireshark; Py/my program/urllib2
makes the initial page request, Proxy replies HTTP Error 407: Proxy
Authentication Required, and Py/my program/urllib2 simply stops at
that, reporting the message/error.

Please forgive me; I've been programming in Python for a few years
now, but never had to deal with Web Proxies.  I *have* tried to RTFMs,
but the "documentation" for non-basic stuffs with urllib2 is... uh...
well, I'm sure ye olde pro's know...  :)


Cheers, and *any* help would be appreciated!
-Larry



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