class static variables and __dict__

[Dustan]

On Feb 16, 5:59 pm, Zack <gol... at gmail.com> wrote:
> Zack wrote:
> > Diez B. Roggisch wrote:
> >> Zack schrieb:
> >>> If I have a class static variable it doesn't show up in the __dict__
> >>> of an instance of that class.
>
> >>> class C:
> >>>    n = 4
>
> >>> x = C()
> >>> print C.__dict__
> >>> {'__module__': '__main__', '__doc__': None, 'n': 4}
> >>> print x.__dict__
> >>> {}
>
> >>> This behavior makes sense to me as n is not encapsulated in x's
> >>> namespace but what method can you use on x to find all available
> >>> attributes for that class?
>
> >> x.__class__.__dict__
>
> >> Diez
>
> > This would leave out any attributes of base classes. Not that I asked
> > for that functionality in my original post but is there a way to get all
> >  attributes qualified by x. ? I see that I could walk the dict of x,
> > x.__class__ and x.__class__.__bases__ until I exhaust the tree. But is
> > there a built in method for doing this?
>
> I believe this accomplishes what I'm looking for. I'm not positive it is
> correct or if there are cases I've missed. It would be nice if there is
> a simple python builtin for finding the fully qualified dict.
>
> def fullDict(obj):
>     '''
>     Returns a dict with all attributes qualified by obj.
>
>     obj is an instance of  a class
>
>     '''
>     d = obj.__dict__
>     # update existing items into new items to preserve inheritance
>     tmpD = obj.__class__.__dict__
>     tmpD.update(d)
>     d = tmpD
>     supers = list(obj.__class__.__bases__)
>     for c in supers:
>        tmpD = c.__dict__
>        tmpD.update(d)
>        d = tmpD
>        supers.extend(c.__bases__)
>     return d

I know you're probably dumping this for dir(), but I should still warn
you: This function modifies the class dictionary, which might not have
been what you intended.