newb loop problem

[Dave]

arrrggg, now I feel really dumb..

hitNum = 0
stopCnt = 6 + hitNum
offSet = 5

for i in range(0,10,1):

	for x in range(hitNum,len(inLst), 1):
		print hitNum, stopCnt
		if x == stopCnt: break
		hitLst.append(inLst[x])
	hitNum +=offSet
	stopCnt+=offSet
print hitLst


Beers, Dave


On Aug 13, 12:58 am, Dave <Nun... at gmail.com> wrote:
> On Aug 13, 12:35 am, Larry Bates <larry.ba... at websafe.com`> wrote:
>
>
>
> > Dave wrote:
> > > Hey there, having a bit of problem iterating through lists before i go
> > > on any further, here is
> > > a snip of the script.
> > > --
> > > d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
> > > c5 d5 e5"
> > > inLst = d.split()
> > > hitLst = []
>
> > > hitNum = 0
> > > stopCnt = 6 + hitNum
>
> > > for i in range(hitNum,len(inLst), 1):
> > >    if i == stopCnt: break
> > >    hitLst.append(inLst[i])
>
> > > print hitLst
> > > --
> > > $ python helper.py
> > > ['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
>
> > > This works fine for my purposes, what I need is an outer loop that
> > > goes through the original list again and appends my next request.
>
> > > ie.
>
> > > hitNum = 5
>
> > > which will return:
>
> > > ['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
>
> > > and append it to the previous one.
>
> > > ie:
>
> > > ['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
> > > ['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
>
> > > not really sure how to do this right now though, been trying several
> > > methods with no good results.
>
> > > btw, just creating lagged values (sort of shift registers) on the
> > > incoming signal
>
> > > Many thanks,
>
> > > Dave
>
> > Dave,
>
> > You are going to need to supply us with more info to help.
>
> > 1) Are you always going to want to get 6 elements from the list
> > 2) Are you always going to want to step by 5 elements as your offset each time
> > through the outer loop?
> > 3) Is your requirement just to split inLst into equal length lists and append
> > them together into a list?
>
> > Depending on your answers this might be quite easy.
>
> > -Larry
>
> Hi Larry, well to answer your questions.
>
> 1) Are you always going to want to get 6 elements from the list
>
> yes for this example, but this will change depending on the length of
> the sig.
> hitNum will be changing depending on what element I need to lag ie:
>
> if hitNum = 1
>
> ['b1', 'c1', 'd1', 'e1', 'a2', 'b2']
>
> so I will be lagging the b elements.
>
> 2) Are you always going to want to step by 5 elements as your offset
> each time
> through the outer loop?
>
> I think I just answered this
>
> 3) Is your requirement just to split inLst into equal length lists and
> append
> them together into a list?
>
> yes
>
> Thanks for all your help,
>
> Dave