a bug in python windows service?

[momobear]

On May 27, 11:25 pm, "Gabriel Genellina" <gagsl-... at yahoo.com.ar>
wrote:
> En Sun, 27 May 2007 09:07:36 -0300, momobear <wgw... at gmail.com> escribió:
>
> >> Instead of extending join(), write a specific method to signal the
> >> quitEvent or just let the caller signal it. And I don't see in this
> >> example why do you need two different events (one on the thread, another
> >> on the service controller), a single event would suffice.
>
> > I don't think a single event is enought, since I think the event
> > python created and windows event are not same kind of event.
>
> They are not the same object, of course (altough the threading.Event
> object relies eventually on a mutex implemented using CreateEvent). But in
> this case both can be successfully used; of course, having the Python
> object a more "pythonic" interfase (not a surprise!), it's easier to use.
> The same example modified using only a threading.Event object (and a few
> messages to verify how it runs):
>
> import threading
>  from win32api import OutputDebugString as ODS
>
> class workingthread(threading.Thread):
>      def __init__(self, quitEvent):
>          self.quitEvent = quitEvent
>          self.waitTime = 1
>          threading.Thread.__init__(self)
>
>      def run(self):
>          while not self.quitEvent.isSet():
>              ODS("Running...\n")
>              self.quitEvent.wait(self.waitTime)
>          ODS("Exit run.\n")
>
> import win32serviceutil
> import win32event
>
> class testTime(win32serviceutil.ServiceFramework):
>      _svc_name_ = "testTime"
>      _svc_display_name_ = "testTime"
>      _svc_deps_ = ["EventLog"]
>
>      def __init__(self, args):
>          win32serviceutil.ServiceFramework.__init__(self, args)
>          self.hWaitStop = threading.Event()
>          self.thread = workingthread(self.hWaitStop)
>
>      def SvcStop(self):
>          self.hWaitStop.set()
>
>      def SvcDoRun(self):
>          self.thread.start()
>          self.hWaitStop.wait()
>          self.thread.join()
>
> if __name__ == '__main__':
>      win32serviceutil.HandleCommandLine(testTime)
>
> --
> Gabriel Genellina

Great! thanks, now I understand the real work of the python windows
service.