how to use Dispatch to open an application in win32com.client

[vithi]

Hi
Since I haven't see any help or tutorial on com there is a application
is installed in the server I am login to the server then what code do
I have to implement to launch the application registered in a server.
how do I write a code to tell my computer to go in to the perticular
server and launch program "XYZ "

do you think this code alone enough to go and look for  xyz
application in the server, I don't get it
Give me any sample code or more help. It help me a lot.
 object = win32com.client.Dispatch("xyz.Application")


On Feb 16, 11:56 pm, "Gabriel Genellina" <gagsl... at yahoo.com.ar>
wrote:
> En Fri, 16 Feb 2007 23:36:26 -0300, vithi <vith... at hotmail.com> escribió:
>
> > I am trying to launch an application. When I try like that
> > When I try like that Excel is opening
> > import win32com.client
> > object = win32com.client.Dispatch("Excel.Application")
> > object.Visible = 1
>
> > But when I try my application which is QeepIt.exe
> > which is in the c:\ drive it is not running
> > Any body tell me how to give path to open an exectable application in
> > Dispatch modules
> > I try like that
> > object = win32com.client.Dispatch("c:\Folder\QeepIt.exe")
> > It give an error.
>
> The above code is used to launch a COM server registered under the name  
> "Excel.Application" and then control it. If you don't know what a COM  
> server is, surely your application can't be used this way.
>
> For launching another program, perhaps sending it some text, and capturing  
> its output, look at the subprocess module. If you are only interested in  
> executing it, with no additional communication, os.system() may be enough.
>
> --
> Gabriel Genellina