sort a list of files

[Scott David Daniels]

Ryan Forsythe wrote:
> Gary Wessle wrote:
>> Hi
>>
>> I am trying to print out the contents of a directory, sorted.
> ...
>> if I remove ".sort()" at the end of line 6 I get an unsorted list of
>> files, if I leave it I get None. who do I fix this?
> 
> `blah.sort()` sorts in-place and returns None. You probably want 
> sorted(blah):
> 
>  >>> a = [3, 1, 4, 1, 5, 9]
>  >>> sorted(a)
> [1, 1, 3, 4, 5, 9]
>  >>> a
> [3, 1, 4, 1, 5, 9]
>  >>> a.sort()
>  >>> a
> [1, 1, 3, 4, 5, 9]

If you are using an old version of Python (2.3.X or before),
the you just need to break your statement up:
Instead of:
     6	print os.listdir(sys.argv[1]).sort()
use:
     6	files = os.listdir(sys.argv[1])
     7	files.sort()
     8	print files

--Scott David Daniels
scott.daniels at acm.org