BCD List to HEX List

[Philippe Martin]

Philippe Martin wrote:

> Hi,
> 
> I'm looking for an algo that would convert a list such as:
> 
> I'm using python to prototype the algo: this will move to C in an embedded
> system where an int has 16 bits - I do not wish to use any python library.
> 
> l1 = [1,2,3,4,6,7,8] #represents the decimal number 12345678
> l2 = func (l1)
> # l2 = [0x1, 0x2, 0xD, 0x6, 0x8, 0x7] #represents 0x12D687
> 
> 
> Regards,
> 
> Philippe

Thanks to all,

I decided to attack the problem another way and change the code in device #2
so it can now take the output from device #1.

As device #2 only needs to compare, add, and subtract the stuff .. it makes
my life much simpler.

Sample (potentially buggy):


l1 = [1,2,3,4]
l2 = [0,2,3,9]


def sup (l1, l2): #assume same length
    for i in range(len(l1) ):
        if l1[i] > l2[i]:
            return 1
        if l1[i] < l2[i]:
            return -1
        return 0



def add (l1, l2): #assume same length
    r = []
    idx =  range (len(l1))
    idx.reverse()
    carry = 0
    for i in idx:
        
        if l1[i] + l2[i] > 10:
            carry = 1
            r.insert(0,(l1[i] + l2[i]) % 10)
        else:
            r.insert(0,l1[i] + l2[i] + carry)
            carry = 0
    return r





print sup(l1,l2)
print add (l1,l2)