"Is" is "is" [was: any way to customize the is operator?]

[Terry Reedy]

"> Lonnie Princehouse wrote:
>> Calling the wrapped version of this function from Python will produce a
>> Python wrapper which represents the same underlying C++ object, but is
>> not actually the same Python object:

What I think you need is a custom version of the .__eq__ (self,other) 
method that pierces thru the wrappers to compare the underlying C++ 
objects.  Then test a == b.

In Python, 'is' specifically means identity of Python objects.