can't pass command-line arguments

BartlebyScrivener rpdooling at gmail.com
Mon Apr 10 09:48:05 EDT 2006


Tim,

No conflicting bat file.

Script name cbfindfiles.py

import os
import fnmatch
import sys

def all_files(root, patterns='*', single_level=False,
yield_folders=False):
    """walks the directory tree starting at root and finds all files
matching patterns"""
    # Expand patterns from semicolon-separated string to list
    patterns = patterns.split(';')
    for path, subdirs, files in os.walk(root):
        if yield_folders:
            files.extend(subdirs)
        files.sort()
        for name in files:
            for pattern in patterns:
                if fnmatch.fnmatch(name, pattern):
                    yield os.path.join(path, name)
                    break
        if single_level:
            break
if __name__ == "__main__":
    print sys.argv
    for path in all_files(sys.argv[1], sys.argv[2]):
        print path

If I run

cbfindfiles.py d:/ *emacs*

from the command prompt I get:

['d:\\python\\cbfindfiles.py', 'd:/', '*emacs*']
followed by a list of matching files

If I run

cbfindfiles d:/ *emacs*

If get an empty command prompt back.

Oh, well.

Not worth troubling over.

Thank you again.

Rick




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