Can't connect to SimpleXMLRPCServer. Help needed.

[Jose Carlos Balderas Alberico]

Thank you for the quick reply John...
Is there a way to sort this out? Should I specify another address here:

server = SimpleXMLRPCServer.SimpleXMLRPCServer(("localhost", 8000), ....)

instead of "localhost" ?

I'm kind of new to client/server programming, so I'm at a loss here.
Thank you very much for your attention.

Jose Carlos.





2006/4/12, John Abel <jabel at plus.net>:
>
> Your server is only listening on 127.0.0.1.
>
> Jose Carlos Balderas Alberico wrote:
> > Up till now I've been setting up my server and client in the same
> > machine, using the "localhost" address for everything.
> > Once I've made it work, I need to move my client application to the
> > computer where it'll be run from, and for some reason, I get a
> > socket.error: (111, 'connection refused').
> >
> > The server is listening on port 8000. I've used the line
> >
> > server = SimpleXMLRPCServer.SimpleXMLRPCServer(("localhost", 8000),
> ....)
> > ##register functions...
> > ...
> > ...
> > server.serve_forever()
> >
> >
> > And the client does the following:
> >
> > host = "XXXX:8000" (where XXXX is the server's IP address)
> > conn = xmlrpclib.connect(host)
> > data = conn.requestData() (requestData is a function previously
> > registered in the server)
> >
> > I've made sure the server is listening on port 8000, since the netstat
> > command says it's listening on port 8000.
> > I've also pinged the server from the client and viceversa and I get an
> > answer. So they can see each other.
> >
> > I've tried looking in google but couldn't find a solution to this
> > problem. Anyone can give me a hand on this?
> > Thank you very much.
> >
> > Jose Carlos.
>
>
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