How to replace all None values with the string "Null" in a dictionary
Steven D'Aprano
steve at REMOVETHIScyber.com.au
Fri Oct 28 19:25:36 EDT 2005
On Fri, 28 Oct 2005 05:23:00 -0700, dcrespo wrote:
>> I think it would be time for you to read the Fine Manual...
>
> hi, thanks for your answer... I really did it the same way you
> suggested, but I forgot to tell you that I wanted to get a better way
> for doing it.
What was wrong with the way you used?
Was it too easy to understand? Not difficult enough? Too few bugs?
You could try something like this:
def substitute(D):
L = D.keys()[:]
i = 0
while (i < len(L)) is True:
key = L[i]
if D[key] == None:
D[key] = 'Null'
else:
del L[i]
i = i + 1
return D
D = {'item1': None, 'item2': 23, 'item3': 42, 'item4': None, 'item5': 15}
print substitute(D)
gives {'item1': 'Null', 'item2': 23, 'item3': 42, 'item4': 'Null',
'item5': 15} as needed.
And I really, really hope this is of no hope whatsoever! ;-)
--
Steven
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